Corrosion with Oxygen If oxygen is present in the water it will react at the cathode: 2H2O + O2 + 4e-  4(OH)-
{"Image DocumentName": "Corrosion with OxygenIf oxygen is present in the water it will react at the cathode: 2H2O + O2 + 4e- \uf0ae 4(OH)-", "Image ImageDescription": "this uses up electrons at the cathode (increasing its potential) and provides hydroxyl ions to react with the iron ions in solution and thus greatly accelerates the corrosion. If there is a good supply of oxygen the final product is ferric hydroxide Fe(OH)3, this is common red rust . If the air supply is limited, however, the product is Fe3O4 which is black rust .", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}