An U, H Example For the reaction, 2CO (g) + O2 (g)  2 CO2 (g), at 298 K qp = -566.0 kJ, calculate qv and w.
{"Image DocumentName": "An \uf044U, \uf044H ExampleFor the reaction, 2CO (g) + O2 (g) \uf0ae 2 CO2 (g), at 298 K qp = kJ, calculate qv and w.", "Image ImageDescription": "Solution: The work is due to change of volume, w = P\uf044V = (nf \u2013 ni) R T = ( 2 \u2013 3)   J mol \u20131 K\u20131   298 K = \u2013 2500 J = \u2013 2 .5 kJ mol \u20131. \uf044H = \u2013 kJ mol \u20131 (of equation) \uf044U = \u2013 \u2013 (\u2013 2.5) kJ = \u2013 kJ. Note: 3 moles of gas is reduced to 2 moles, work must be done to the system to compress it back to the same P, w is positive. 2CO (g) + O2 (g) \uf044H. \uf044U. w. 2CO2 (g) Thermochemistry.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}