Codes de Hamming : en pratique (4)
{"Image DocumentName": "Codes de Hamming : en pratique (4)", "Image ImageDescription": "\u00e9. \u00eb. \u00ea. \u00f9. \u00fb. \u00fa. c4. c5. c6. c1. c2. c3. En verif : la premi\u00e8re colonne de H ajoute les termes en c0 qui vaut 0. := H. \u00e9. \u00eb. \u00ea. \u00f9. \u00fb. \u00fa. 1. \u00e9. \u00eb. \u00ea. \u00f9. \u00fb. \u00fa. + c1. c2. c3. c4. c5. c6. Comme c0 =0, on peut supprimer la premi\u00e8re colonne de H. \u00e9. \u00eb. \u00ea. \u00f9. \u00fb. \u00fa. c4. c5. c6. c1. c2. c3. \u00e9 \u00f9. \u00e9. \u00eb. \u00ea. \u00f9. \u00fb. \u00fa. + c1. c2. c3. c4. c5. c6. \u00ea. \u00fa. \u00ea. \u00fa. H. := \u00ea \u00fa. \u00ea. \u00fa. \u00ea. \u00fa. \u00eb \u00fb.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}