Time-Residual Drawdown Analysis For a constant rate of pumping (Q), the recovery any time (t) after pumping stops: T = Q 4 s For the example, s r = 5.
{"Image DocumentName": "Time-Residual Drawdown Analysis", "Image ImageDescription": "For a constant rate of pumping (Q), the recovery any time (t\u2019) after pumping stops: T = Q. 4pDs\u2019 For the example, Dsr = 5.2 m and Q = 1100 m3/d so: T = 1100 / (12.56 x 5.2) = 17 m2/d. Notice that the graph plots t/t\u2019 so the points on the LHS represent long recovery times and those on the RHS short recovery times. The storage coefficient cannot be estimated for the residual drawdown plot because the intercept t / t\u2019 \uf0ae 1 as t\u2019 \uf0ae \uf0a5. This more obvious, remembering t\u2019 = t - tr where tr is the elapsed pumping time before recovery starts.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}