We need to substitute one equation into the other to eliminate a variable.
{"Image DocumentName": "We need to substitute one equation into the other to eliminate a variable.", "Image ImageDescription": "4 = 2\u03c0r + 4x Area = \u03c0r2 + x2 Let\u2019s take a look at the 2nd derivative at x=1 to verify x=1 is a max. Area\u2019\u2019 = 2. Area\u2019\u2019(1) = 2. Since Area\u2019\u2019 is positive the face is smiling, the graph is concave up, and therefore x=1 is a minimum, instead of a maximum!! Let\u2019s take a look at the graph. Consider the restrictions\u2026 On a closed interval where are the possible locations of the extrema? Critical Numbers. Endpoints. The best solution here is x = 0. The circle gets everything.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}