Calculating Ksp From Molar Solubility
{"Image DocumentName": "Calculating Ksp From Molar Solubility", "Image ImageDescription": "It is found that 1.2x10-3 mol of lead (II) iodide, PbI2, dissolves in 1.0 L of aqueous solution at 25 oC. What is the Ksp at this temperature? PbI2 \uf0f3 Pb2+ + 2I- 2 iodide ions form, so you must multiply molarity by 2! Ksp = [Pb2+][I-]2. Ksp = [1.2 x 10-3] [2(1.2 x 10-3)]2. Ksp = 6.9 x 10-9.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}