Step1 MR x = 0.2 sin 30° = 0.10 m At the end of stance phase while running, F g,x under the right foot is 200N and F g,y is 350N. F g is applied to th
{"Image DocumentName": "At the end of stance phase while running, Fg,x under the right foot is 200N and Fg,y is 350N. Fg is applied to the foot 0.2 m from the ankle. What is the ankle torque due to Fg?", "Image ImageDescription": "Step1. MRx = 0.2 sin 30\u00b0 = 0.10 m. 30\u00b0 350N. 200N. MRx. 0.2 m.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}