Equimolar mixture of two gases `A_(2)` and `B_(2)` is taken in a rigid vessel at temperature 300 K. The gases reacts according to given equations : <br> `A_(2)(g)hArr2 A (g)`        `K_(P1)=?` <br> `B_(2)(g)hArr2 B (g)`        `K_(P2)=?` <br> `A_(2)(g)+B_(2)(g)hArr2 AB (g)`        `K_(P3)=2` <br> If the initial pressure in the container was 2 atm and final pressure developed at equilibrium is 2.75 atm. in which equilibrium partial pressure of gas AB was 0.5 atm, calculate the ratio of `(K_(P2))/(K_(P1))` <br> [Given : Degree of dissociation of `B_(2)` is greater than `A_(2)`].
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