Ram weight – Drop height If the pile is struck by an impact velocity of 3 m/s the force in the pile will be: F=3*566=1698 kN To achieve this partical velocity (force) the drop height has to be: H=v 2 /2g = 3 2 /2*10 = 0,45 m Due to loss of energy in the cap, cushioning and so forth the drop height has to be higher
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