& 2x+3y = 5\\& 2({\color{red}3})+3y = 5 && \text{Substitute in the value for} \ x.\\& {\color{red}6}+3y = 5 && \text{Multiply the value of} \ x \ \text{by the coefficient} \ (2).\\& 6 {\color{red}-6}+3y = 5 {\color{red}-6} && \text{Isolate the variable} \ y.\\& 3y = {\color{red}-1} && \text{Solve the equation.}\\& \frac{3y}{{\color{red}3}} = \frac{-1}{{\color{red}3}}\\& \frac{\cancel{3}y}{\cancel{3}} = {\color{red}-\frac{1}{3}}\\& \boxed{y = -\frac{1}{3}}
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