H2(g) + F2(g)  2 HFSolution Based on the bond energies given, we have. H2  2H D = 436 kJ/mol.
{"Image DocumentName": "H2(g) + F2(g) \uf0ae 2 HFSolution Based on the bond energies given, we have. H2 \uf0ae 2H D = 436 kJ/mol.", "Image ImageDescription": "F2 \uf0ae 2F D = 158 kJ/mol. 2H + 2F \uf0ae 2HF H = -568 kJ/mol   2 = Adding all three equations and energies. H2(g) + F2(g) = 2 HF \u0394H = -542 kJ/equation. Note that D represent bond dissociation energy, and H the enthalpy of the reaction as written. We use \u0394H in the last equation to denote enthalpy of change of the overall reaction.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}